$\dfrac{11}{7}\times\dfrac{2}{3}$ =

$33 \times\dfrac{6}{-99}$ =

$\dfrac{2}{39}\times 7$ =

$7 \times\dfrac{21}{49}$ =

$\dfrac{-5}{4}\times\dfrac{-3}{2}$ =

$\dfrac{3}{2}\times\dfrac{33}{19}$ =

$\dfrac{23}{13}\times\dfrac{2}{4}$ =

$\dfrac{19}{4}\times\dfrac{2}{17}$ =

$\dfrac{1}{2}\times\dfrac{17}{2}$ =

$\dfrac{11}{5}\times\dfrac{15}{10}$ =