$3 \times\dfrac{19}{-19}$ =

$3 \times\dfrac{15}{9}$ =

$\dfrac{11}{36}\times 7$ =

$\dfrac{7}{2}\times\dfrac{7}{2}$ =

$\dfrac{4}{10}\times\dfrac{6}{7}$ =

$\dfrac{-3}{5}\times\dfrac{11}{-7}$ =

$\dfrac{11}{5}\times\dfrac{4}{3}$ =

$\dfrac{11}{6}\times\dfrac{21}{17}$ =

$\dfrac{6}{9}\times\dfrac{4}{7}$ =

$\dfrac{17}{3}\times\dfrac{2}{3}$ =