$\dfrac{3}{34}\times 7$ =

$\dfrac{5}{33}\times\dfrac{2}{3}$ =

$\dfrac{3}{6}\times\dfrac{19}{14}$ =

$\dfrac{11}{3}\times\dfrac{2}{5}$ =

$\dfrac{7}{25}\times\dfrac{35}{11}$ =

$7 \times\dfrac{-21}{49}$ =

$15 \times\dfrac{9}{27}$ =

$\dfrac{9}{7}\times\dfrac{22}{15}$ =

$\dfrac{7}{-2}\times\dfrac{-7}{15}$ =

$\dfrac{3}{2}\times\dfrac{11}{4}$ =